To solve a linear equation like #16-2.4d=-8#, we should all constant terms to one side and variable term to other side. Here we have two negative terms #-2.4d# and #-8#, so we add #2.4d+8# on both sides, which gives us

#16-2.4d+2.4d+8=2.4d+8-8# or

#16-cancel(2.4d)+cancel(2.4d)+8=2.4d+cancel8-cancel8# or

#16+8=2.4d# and reversing LHS and RHS, we get

#2.4d=24# or

#d=24-:2.4=24-:24/10=24xx10/24=cancel24xx10/cancel24=10#

Hence, #d=10#.

To check the answer, let us put #d=10# in LHS. Then

#LHS=16-2.4d=16-2.4xx10=16-24=-8=RHS#

Hence the solution #d=10# is correct.